Structures - 2 College Details

Problem Description

Create a structure called College.

struct College
{
char name[100];
char city[100];
int establishmentYear;
float passPercentage;
}

The structure variable name "S1"

Write a program to get the details of n colleges and to display their details, sorted by college name in ascending order.

Input and Output Format:

Refer sample input and output for formatting specification.
All float values are displayed correct to 2 decimal places.
All text in bold corresponds to input and the rest corresponds to output.

Hint: The college name should be in Sorted or in Ascending Order
College details are sorted based on their "Names" in ascending order

In Test case 1:
S comes before T (A B C D E F G H I J K L M N O P Q R S T)

In Test case 2:
A,K,S(A B C D E F G H I J K L M N O P Q R S T)

Note: The structure variables, data members and structure name are CASE Sensitive.

Follow the same case mentioned in the mandatory

Test Case 1

Input (stdin)

2

SRMUniversity Chennai 1985 97.6

TRPEngineeringCollege Trichy 1998 97.2

Expected Output

Details of colleges

Name:SRMUniversity

City:Chennai

Year of establishment:1985

Pass percentage:97.6

Name:TRPEngineeringCollege

City:Trichy

Year of establishment:1998

Pass percentage:97.2

Test Case 2

Input (stdin)

3

Karunyauniversity Coimbatore 1986 67.2

SastraUniversity Trichy 1987 77.3

Amritauniversity Coimbatore 1988 90.1

Expected Output

Details of colleges

Name:Amritauniversity

City:Coimbatore

Year of establishment:1988

Pass percentage:90.1

Name:Karunyauniversity

City:Coimbatore

Year of establishment:1986

Pass percentage:67.2

Name:SastraUniversity

City:Trichy

Year of establishment:1987

Solution

#include<stdio.h>
#include<string.h>
struct College{char name[100];
              char city[100];
               int establishmentYear;
               float passPercentage;
              }S1[20],temp;
int main(){
  
  int n,i,j;
      printf("Details of colleges\n");
  scanf("%d",&n);
  for(i=0;i<n;i++){
  scanf("%s %s %d %f",S1[i].name,S1[i].city,&S1[i].establishmentYear,&S1[i].passPercentage);
  }
   for (i = 1; i < n; i++)
      for (j = 0; j < n - i; j++) {
         if (strcmp(S1[j].name, S1[j + 1].name) > 0) {
            temp = S1[j];
            S1[j] = S1[j + 1];
            S1[j + 1] = temp;
         }
      }
 
   for (i = 0; i < n; i++) {
      printf("Name:%s\nCity:%s\nYear of establishment:%d\nPass percentage:%.1f\n",S1[i].name,S1[i].city,S1[i].establishmentYear,S1[i].passPercentage);
   }
  return 0;
}