Case Count

Problem Description 

C PROGRAM TO COUNT NUMBER OF UPPERCASE AND LOWERCASE LETTERS FROM A SENTENCE 

Test Case 1
 Input (stdin) 
Arun IS a GooD

Expected Output
 Uppercase Letters=5
 Lowercase Letters=6 

Test Case 2 
Input (stdin)
 HELLO SRMM CHENN

Expected Output
 Uppercase Letters=14
 Lowercase Letters=0

Solution

#include <stdio.h>

int main()

{

char str[100];

int countL,countU;

int counter;

countL=countU=0;

scanf ("%[^\n]s",str);

for(counter=0;str[counter]!=NULL;counter++){

if(str[counter]>='A' && str[counter]<='Z')

countU++;

else if(str[counter]>='a' && str[counter]<='z')

countL++;

}

printf("Uppercase Letters=%d\nLowerCase Letters=%d",countU,countL);

return 0;

}