Find the Year

• Problem Description

  
  Most years have 365 days. However, the time required for the Earth to orbit the Sun is actually slightly more than that. As a result, an extra day, February 29, is included in some years to correct for this difference. Such years are referred to as leap years.
  
  The rules for determining whether or not a year is a leap year follow:
  
  Any year that is divisible by 400 is a leap year.
  Of the remaining years, any year that is divisible by 100 is not a leap year.
  Of the remaining years, any year that is divisible by 4 is a leap year.
  All other years are not leap years.
  
  Write a program that reads a year from the user and displays a message indicating
  whether or not it is a leap year.

• Test Case 1

  
  Input (stdin)

  2016
  
  

  Expected Output

  Yes

• Test Case 2

  
  Input (stdin)

  2001
  
  

  Expected Output

  No

Solution

#include <stdio.h>

int main()

{

  int year;

  scanf("%d",&year);

  if(year%4==0)

  {

    printf("Yes");

  }

  else

    printf("No");

  return 0;

}